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65 brainleiest! Can someone help?!

65 brainleiest! Can someone help?!-example-1
User Monergy
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1 Answer

26 votes
26 votes

Answer:

m∡EFG = 139°, and m∡ IFH = 49°

Explanation:

We know that vertical angles are congruent so we can say that

∡EFG ≅∡DFH and that ∡EFD≅∡GFH

Congruent angles have the same measure therefore

∡EFG = ∡DFH = 6x+25 and

∡EFD = ∡GFH = 2x+3

Use that all those angles add up to 360° to find x

∡EFG +∡GFH +∡DFH + ∡EFD = 360°, substitute the given measures

6x+25 +2x+3 + 6x+25 +2x+ 3 = 360 , combine like terms

16x + 56 = 360, subtract 56 from both sides

16x = 304, divide both sides by 16

x = 19

m∡EFG = 6x +25 , substitute x with 19 and calculate

m∡EFG = 6·19 +25

m∡EFG = 139°

m∡ IFH = 90°- m∡GFH, substitute m∡GFH with 2x+3

m∡ IFH = 90°- (2x +3), substitute x with 19

m∡ IFH = 90°- (2·19 +3)

m∡ IFH = 90°- 41

m∡ IFH = 49°

User Dingalla
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