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A 7.12 μC charge is moving at the speed of light in a magnetic field of 4.02 mT. What is the force on the charge?

User Fyr
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1 Answer

2 votes

Answer:

858.7 N

Step-by-step explanation:

The magnetic force on the charge F = Bqv where B = magnetic field strength = 4.02 mT = 4.02 × 10⁻³ T, q = charge = 7.12 μC = 7.12 × 10⁻⁶ C and v = c = speed of light = 3 × 10⁸ m/s

F = Bqc

= 4.02 × 10⁻³ T × 7.12 × 10⁻⁶ C × 3 × 10⁸ m/s

= 858.7 N

User Ashishsingh
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