Question

Find the solution(s) to x^2- 14x + 49 = 0.

O A. x=-2 and x = 7
B. x= -1 and x = 14
C. x= 7 only
D. x = 7 and x = -7

Answer 1

`\boxed{C. \: x = 7 \: only}`

Explanation:

`= > {x}^(2) - 14x + 49 = 0 \\ \\ = > {x}^(2) - (7 + 7)x + 49 = 0 \\ \\ = > {x}^(2) - 7x - 7x + 49 = 0 \\ \\ = > x(x - 7) - 7(x - 7) = 0 \\ \\ = > (x - 7)(x - 7) = 0 \\ \\ = > {(x - 7)}^(2) = 0 \\ \\ = > x - 7 = 0 \\ \\ = > x = 7`