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A catapult launches a boulder with an upward velocity of 120 ft/s. The height of the boulder, h, in feet after t seconds is given by the function h = -16t^2 + 120t + 10. How long does it take to reach maximum height? What is the boulder's maximum height? What is the boulder's maximum height? Round to the nearest hundredth, if necessary.

User Psv
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User Janitza
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Answer:

See below in bold.

Explanation:

h = -16t^2 + 120t + 10

To find the height and time for maximum we convert to vertex form:

h = -16(t^2 - 7.5t) + 10

h = -16 [(t - 3.75)^2 - 14.0625] + 10

h = -16(t - 3.75)^2 + 225 + 10

h = -16(t - 3.75)^2 + 235

So the time to reach maximum height is 3.75 seconds and the maximum height = 235 ft.

User Sasidharan
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