Question

Consider The reaction Cu2O(s) + C (s) ------> 2 Cu (s) + CO (g)

When 11,5 g of C are allowed to react with 114,5 g of Cu2O, 87,4 g of Cu are obtained.Find

the limiting reactant,

Answer 1

Carbon is the limiting reagent

Step-by-step explanation:

Answer 2

Cu2O (s) + C (s) ----> 2Cu (s) + CO (g)

Find the moles of each:

11.5g of Carbon

n(C) = mass / Molar mass

n(C) = 11.5 / 12.01 = 0.95753587

114.5g of Copper I Oxide

n(Cu2O) = mass / Molar mass

n(Cu2O) = 114.5 / 143.1 = 0.800139762

87.4g of Copper

n(Cu) = mass / Molar mass

n(Cu) = 87.4 / 63.55 = 1.375295043

Carbon has less moles compared to Copper I Oxide, therefore Carbon is the limiting reagent