Question

You’re trying to remove dissolved iron from a solution. The theoretical yield for a reaction between sodium sulfide and iron(III) bromide is 0.721 kilogram of solid iron(II) sulfide. When you carried out the reaction, you got 530.0 grams. What is the percent yield?

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ANSWER!!!
The percent yield of the reaction is 73.5%

Answer 1

73.5%

Step-by-step explanation:

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Answer 2

73.5%

Step-by-step explanation:

Step 1:

Data obtained from the question.

Theoretical yield = 0.721Kg

Actual yield = 530g

Percentage yield =..?

Step 2:

Conversion of 0.721Kg to grams. This is illustrated below:

1Kg = 1000g

Therefore, 0.721Kg = 0.721 x 1000 = 721g

Step 3:

Determination of the percentage yield.

The percentage yield can be obtained by using the following formula:

Percentage yield = Actual yield /Theoretical yield x 100

Percentage yield = 530/721 x 100

Percentage yield = 73.5%

Therefore, the percentage yield is 73.5%