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John and Trey both leave the coffee shop at the same time, but in opposite directions. If Trey travels 7 mph faster than John and after 5 hours they are 85 miles apart, how fast is each traveling?

John is traveling __________ mph

Trey is traveling __________ mph

User Benjen
by
5.8k points

1 Answer

2 votes

Answer:

John is traveling 5 mph

Trey is traveling 12 mph

Explanation:

we will concept of speed distance and time where

distance = speed * time

Let the speed of john be x miles per hour

if, Trey travels 7 mph faster than John

then speed of trey = (x+7) miles per hour

Time of travel for both of them = 5 hours

distance traveled by john in 5 hours = x* 5 = 5x miles

distance traveled by john in 5 hours = (x+7) * 5 = (5x + 35)miles

total distance covered by them = 5x miles + (5x + 35)miles = (10x+35) miles

it is given that after 5 hours they were 85 miles apart, thus the distance above calculated should be equal to 85 miles

10x+35 = 85

=>10x = 85 -35

=> 10x = 50

=> x = 50/10

=> x = 5

Thus, speed of john is 5 miles per hour

speed of Trey is: x+7= 5 + 7 = 12 miles per hour

User Onassar
by
6.6k points
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