Question

If 200 mL of 3M CaCO3 is diluted to 250 mL, what is the new molarity?

Answer 1

Answer: The new molarity is 2.4 M

Step-by-step explanation:

According to the dilution law,

`C_1V_1=C_2V_2`

where,

`C_1` = concentration of pure solution = 3 M

`V_1` = volume of pure solution = 200 ml

`C_2` = concentration of diluted solution= ?

`V_2` = volume of diluted solution= 250 ml

Putting in the values:

`3M* 200ml=M_2* 250ml`

`M_2=2.4M`

Thus the new molarity is 2.4 M