Question

The graph of which function passes through the point (0,2/pi)?

y=cos-1(x)
y=csc-1(x)
y=sec-1(x)
y=sin-1(x)
thanks!

Answer 1

Answer:it’s A y=cos^1(x)

Explanation:

Edge 2020

Answer 2

`y=sin^(-1)x`

Explanation:

Given: A point is
`(0,2\pi)`

To find: function whose graph passes through the given point

Solution:

A trigonometry explains the relationship between the sides and the angles of the triangle.

The inverse trigonometric functions
`sin^(-1)x\,,\,cos^(-1)x\,,\,tan^(-1)x` help to find the value of an unknown angle of a right triangle when length of two sides are given.

Consider
`\sin y=x`

Put
`y=2\pi`

`sin 2\pi=0`

So, point
`(0,2\pi)` satisfies the function
`y=sin^(-1)x`

Therefore, graph of function
`y=sin^(-1)x` passes through
`(0,2\pi)`