Question

g 1. An ideal gas is confined to a container with adjustable volume. The number of moles, n, and temperature, T, are constant. By what factor will the volume change if pressure decreases by a factor of 8.5 Hint: pV

Answer 1

Increases by a factor of 8.5

Step-by-step explanation:

Hello,

In this case, with the given data, we can apply the Boyle's law in order to understand the pressure-volume behavior as an inversely proportional relationship:

`P_1V_1=P_2V_2`

Thus, for the given pressure decrease we have:

`P_2=(P_1)/(8.5)`

So the volume changes by:

`V_2=(P_1V_1)/((P_1)/(8.5) ) \\\\V_2=8.5V_1`

Therefore, it increases by a factor of 8.5.

Regards.

Answer 2

The volume will increase by a factor of 8.5

Step-by-step explanation:

In an ideal gas, the volume is inversely proportional to the pressure. This means that the volume will decrease when the pressure increases and vice versa.

Let the initial volume be v1, and the initial pressure p1.

the final pressure is decreased by a factor of 8.5, i.e

p2 = p1/8.5 = 0.12p1

using p1v1 = p2v2

v2 = (p1/p2)v1

v2 = (p1/0.12p1)v1

v2 = 8.5v1

This means that the final pressure increases by a factor of 8.5