Question

What is the volume of a 4.0M solution that contains 374 grams of KNO3?'

Answer 1

THE VOLUME OF A 4 M SOLUTION THAT CONTAINS 374 g OF KNO3 IS 0.93 L

Step-by-step explanation:

Number of moles = concentraion * volume

Number of moles can also be written as:

number of moles = mass / molar mass

Calculate the molar mass of KNO3 where (K = 39, N = 14, 0=16)

molar mass of KNO3 = (39 + 14 + 16*3) = 101 g/mol

So therefore:

mass / molar mass = concentration * volume

where;

mass = 374 g

molar mass = 101 g/mol

concentration = 4 M

volume = unknown

Hence,

374 / 101 = 4 * V

V = 374 / 101 * 4

V = 374 / 404

V = 0.9257 dm3

The volume of a 4M solution that contains 364 g of KNO3 is approximately 0.93 L

Answer 2

0.93L

Step-by-step explanation:

We'll begin by calculating the number of mole of present 374g of KNO3. This is illustrated below:

Mass of KNO3 = 374g

Molar mass of KNO3 = 39 + 14 + (16x3) = 101g/mol

Number of mole of KNO3 =..?

Mole = Mass /Molar Mass

Number of mole of KNO3 = 374/101 = 3.7 moles

Now, we can calculate the volume of the solution as follow:

Mole of KNO3 = 3.7 moles

Molarity = 4M

Volume =..?

Volume = mole /Molarity

Volume = 3.7/4

Volume = 0.93L

Therefore, the volume of the solution is 0.93L