Final answer:
Using Boyle's law, the final volume of the weather balloon when the pressure decreases to 60.8 kPa is calculated to be approximately 3160.9 L, assuming no change in temperature and gas amount.
Step-by-step explanation:
The question pertains to the ideal gas law and how changes in pressure affect the volume of a gas when temperature and the amount of gas remain constant. To solve for the final volume of the weather balloon, we can use Boyle's law, which states that the pressure of a gas is inversely proportional to its volume when temperature is held constant (P1V1 = P2V2).
The initial pressure (P1) is 96.3 kPa, and the initial volume (V1) is 2000 L. The final pressure (P2) is 60.8 kPa, and we are solving for the final volume (V2).
Applying Boyle's law, we can calculate V2 as follows:
V2 = (P1 × V1) / P2
V2 = (96.3 kPa × 2000 L) / 60.8 kPa
V2 = 3160.9 L (rounded to one decimal place)
Therefore, the final volume of the weather balloon when the pressure decreases to 60.8 kPa is approximately 3160.9 L.