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A 64.7 cm long straight section of wire is located entirely inside a uniform magnetic field of |B| = 0.370 T. The wire is perpendicular to the direction of the magnetic field. When a current runs through the wire a magnetic force of |F| = 0.110 N acts on that section of wire. Calculate the size of the current.

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Answer:

The current is
I = 0.4595 \ A

Step-by-step explanation:

From the question we are told that

The length of the wire is
L = 64.7 \ cm = 0.647 \ m

The magnetic field is
B = 0.370 \ T

The magnetic force is
F = 0.110 \ N

Generally the magnetic force exerted by the field is mathematically represented as


F = IL B sin \theta

Making I the subject we have


I = (F)/(LB \ sin\theta)

The angle here is 90° since the wire is perpendicular to the direction of the magnetic field

Substituting values


I = (0.110)/( (0.370) * 0.647 \ sin(90))


I = 0.4595 \ A

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