Question

11 grams of carbon dioxide, CO2, is dissolved in 1000 mL of solution. Determine the molarity (M).​

Answer 1

Answer: The molarity is 0.25 M

Step-by-step explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

`Molarity=(n* 1000)/(V_s)`

where,

n = moles of solute

`V_s` = volume of solution in ml

moles of
`CO_2` =
`\frac{\text {given mass}}{\text {Molar mass}}=(11g)/(44g/mol)=0.25mol`

Now put all the given values in the formula of molality, we get

`Molarity=(0.25* 1000)/(1000ml)`

`Molarity=0.25M`

Therefore, the molarity is 0.25 M