Answer:
68.11% probability that the firm involved is firm B
Explanation:
Bayes Theorem:
Two events, A and B.
![P(B|A) = (P(B)*P(A|B))/(P(A))](https://img.qammunity.org/2021/formulas/mathematics/college/dpl2om35c6759cj1w3kaim008n3d4pjd3q.png)
In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.
In this question:
Event A: Cost overrun
Event B: Agency B used.
A certain federal agency employs three consulting firms (A, B and C) with probabilities 0.40, 0.45 and 0.15.
This means that
![P(B) = 0.45](https://img.qammunity.org/2021/formulas/mathematics/college/zrvowjn8e4pxb0zjc4y5byew7p0qiyw55e.png)
From past experiences, it is known that the probability of cost overruns for the firms are 0.01, 0.14, and 0.17, respectively.
This means that
![P(A|B) = 0.14](https://img.qammunity.org/2021/formulas/mathematics/college/1hlfv32g36c9twvgb259ywxl9mcgdz1039.png)
Probability of cost overrun.
Firm A is used 40% of the time, with 1% of these having cost overrun. B is used 45%, with 14% of these having cost overruns. C is used 15% of the time, with 17% of these having cost overruns.
So
![P(A) = 0.4*0.01 + 0.45*0.14 + 0.15*0.17 = 0.0925](https://img.qammunity.org/2021/formulas/mathematics/college/safm0lsvnyedy18z0wk1z1bf45j9bv40zv.png)
What is the probability that the firm involved is firm B
![P(B|A) = (0.45*0.14)/(0.0925) = 0.6811](https://img.qammunity.org/2021/formulas/mathematics/college/tuyglym6yi658dkdk9zkeva6574xpitxp6.png)
68.11% probability that the firm involved is firm B