Question

Calculate the Reynold's number using a viscosity of air as 1.81E-05 kilograms/(meters-seconds), the density of air (see above), the diameter as 0.15 m, and, from the data, 0.89 m/s.

Answer 1

8924.6

Step-by-step explanation:

We are given that

Viscosity of air,
`\eta=1.81* 10^(-5)kg/m-s`

Density of air,
`\rho=1.21kg/m^3`

Diameter,d=0.15 m

v=0.89m/s

We have to find the Reynold's number.

Reynold's number,R=
`(\rho vd)/(\eta)`

Substitute the values then we get

`R=(1.21* 0.89* 0.15)/(1.81* 10^(-5))`

R=
`8924.6`

Hence, the value of Reynold's number=8924.6