Question

u make 1.000 L of an aqueous solution that contains 35.0 g of sucrose (C12H22O11).Part AWhat is the molarity of sucrose in this solution?Express your answer to three significant figures.M

Answer 1

0.102 M

Step-by-step explanation:

Given data

• Mass of sucrose (solute): 35.0 g

• Volume of solution: 1.000 L

Step 1: Calculate the moles of solute

The molar mass of sucrose is 342.3 g/mol. The moles corresponding to 35.0 g of sucrose are:

`35.0g * (1mol)/(342.3g) =0.102mol`

Step 2: Calculate the molarity of sucrose in the solution

The molarity is equal to the moles of solute divided by the liters of solution.

`M=(0.102mol)/(1.000L) =0.102 M`