Explanation:
Given that n! = n(n - 1)(n - 2)(n - 3)...2×1
We want to show that 2n - 1 ≤ n!
Since
n! = n(n - 1)(n - 2)(n - 3)...2×1
= n(n - 1)!
n! = n(n - 1)(n - 2)!
n! = (n² - n)(n - 2)!
From here obviously,
n! ≥ n
n! ≥ 2n
And
n! ≥ 2n - 1
Which implies
2n - 1 ≤ n!