Question

A projectile is fired with an initial speed of 37.7 m/s at an angle of 41.2° above the horizontal on a long flat firing range. Determine the maximum height reached by the projectile.

Answer 1

h = 31.46 m

Step-by-step explanation:

We have,

Initial speed of a projectile is 37.7 m/s

It was projected at an angle of 41.2° above the horizontal on a long flat firing range.

It is required to find the maximum height reached by the projectile. The formula used to find it is given by :

`h=(u^2\sin^2\theta)/(2g)`

Plugging all the known values,

`h=((37.7)^2* \sin^2(41.2))/(2* 9.8)\\\\h=31.46\ m`

So, the maximum height reached by the projectile is 31.46 m.