Question

The ideal mass for a piece of chocolate is 2.5 ounces. The actual mass for a production can vary by, at most, 0.08

ounces. Create an absolute value inequality and solve it to determine the range of chocolate masses.​

Answer 1

`2.42\,oz \leq m_(real) \leq 2.58\,oz`

Explanation:

The inequality must be the absolute value of the difference between real mass and ideal mass less or equal to 0.08 ounces. That is to say:

`|m_(real) - m_(ideal)| \leq 0.08\,oz`

`|m_(real) - 2.5\,oz| \leq 0.08\,oz`

There are two extreme cases:

`m_(real,max) - 2.5\,oz = 0.08\,oz` and
`m_(real, min) - 2.5\,oz = -0.08\,oz`

`m_(real, max) = 2.58\,oz` and
`m_(real,min) = 2.42\,oz`

Range of chocolate masses must be:

`m_(real, min) \leq m_(real) \leq m_(real,max)`

`2.42\,oz \leq m_(real) \leq 2.58\,oz`