The ideal mass for a piece of chocolate is 2.5 ounces. The actual mass for a production can vary by, at most, 0.08 ounces. Create an absolute value inequality and solve it to de…

Question

asked Nov 17, 2021 37.7k views

1 Answer

SunnyShah · Answer 1 · 2021-11-23T21:24:39+0000

Answer:

$2.42\,oz \leq m_(real) \leq 2.58\,oz$

Explanation:

The inequality must be the absolute value of the difference between real mass and ideal mass less or equal to 0.08 ounces. That is to say:

$|m_(real) - m_(ideal)| \leq 0.08\,oz$

$|m_(real) - 2.5\,oz| \leq 0.08\,oz$

There are two extreme cases:

$m_(real,max) - 2.5\,oz = 0.08\,oz$ and
$m_(real, min) - 2.5\,oz = -0.08\,oz$

$m_(real, max) = 2.58\,oz$ and
$m_(real,min) = 2.42\,oz$

Range of chocolate masses must be:

$m_(real, min) \leq m_(real) \leq m_(real,max)$

$2.42\,oz \leq m_(real) \leq 2.58\,oz$