Question

standing on a hill that is 3.5 m high above level ground. A wall that is on level ground is 15 m away from the student. The student decides to throw a ball horizontally at a combined height of 4.5 m, at the wall. The student measures the time it takes to make an impact and finds it to be 0.65 s. At what height, from the ground, did the student hit the side of the wal

Answer 1

The height will be "2.42 m".

Step-by-step explanation:

The given values are:

time, t = 0.65 seconds

∴ g = 9.8

As we know,

⇒
`x=vt+(1)/(2)gt^2`

∴ v = 0

On putting the estimated values, we get

⇒
`=0+(1)/(2)* 9.8* (0.65)^2`

⇒
`=(1)/(2)* 9.8* 0.4225`

⇒
`=(1)/(2)* 4.1405`

⇒
`=2.07025 \ m`

Now,

Height,
`h=4.5-2.07025`

⇒
`=2.42 \ m`