Question

Cheetahs, the fastest of the great cats, can reach 50.0 miles/hour in 2.22 s starting from rest. Assuming that they have constant acceleration throughout that time, find their acceleration in meters per second squared.

Answer 1

The acceleration of the Cheetah is found to be 10.07 m/s²

Step-by-step explanation:

We have the following data in this question:

Vf = Final Velocity of the Cheetah = 50 miles/hr

Vf = (50 miles/hr)(1 hr/ 3600 s)(1609.34 m/1 mile)

Vf = 22.35 m/s

Vi = Initial Speed of Cheetah = 0 m/s (Since, Cheetah starts from rest)

t = time interval passed = 2.22 s

So, in order to find the acceleration, we simply use the formula for acceleration, that is:

Acceleration = a = (Vf - Vi)/t

a = (22.35 m/s - 0 m/s)/2.22 s

a = 10.07 m/s²

The acceleration of the Cheetah is found to be 10.07 m/s²

Answer 2

`10.07m/s^2`

Step-by-step explanation:

Information we have:

velocities:

initial velocity:
`v_(i)=0mph` (starts from rest)

final velocity:
`v_(f)=50mph`

time:
`t=2.22s`

Since we need the answer in
`m/s^2`, we nees to convert the speed to meters per second:

`v_(f)=(50miles)/(1hour)((1hour)/(3,600s) )((1609.34meters)/(1mile) ) \\\\v_(f)=(50*1609.34)/(3600) m/s\\\\v_(f)=22.35m/s`

We find the acceleration with the following formula:

`a=(v_(f)-v_(i))/(t)`

substituting the known values:

`a=(22.35m/s-0m/s)/(2.22s)\\ \\a=10.07m/s^2`

the acceleration is 10.07
`m/s^2`