Question

A 3650​-year-old wooden chest is found by archaeologists. What percentage of the original Superscript 14 Baseline Upper C would you expect to find in the wooden​ chest? (Recall that the decay constant for Superscript 14 Baseline Upper C is​ 0.00012.)

Answer 1

64.5%

Explanation:

Initial amount N° = ?

Remaining amount after decay = N = ?

k = decay constant = 0.00012
`yr^(-1)`

t = time = 3650​ year

fraction remaining will be N/N°

From the decay equation, N = N°
`e^(-kt)`

N/N° =
`e^(-kt)`

N/N° =
`e^(-0.00012 x 3650 )`

N/N° =
`e^(-0.438)`

N/N° = 0.645 = 64.5%