Answer:
4. 13.04m/s²
5. 4x10^11m/s²
6. –3m/s²
Step-by-step explanation:
Acceleration is defined as rate of change of velocity with time. Mathematically it is represented as:
a = (v – u)/t
a is the acceleration.
v is the final velocity.
u is the initial velocity.
t is the time
With the above formula, we can obtain the acceleration of each question.
4. Determination of the acceleration of the spacecraft.
Data obtained from the question include the following:
Initial velocity (u) = 0
Final velocity (v) = 67.8m/s
Time (t) = 5.2secs
Acceleration (a) =..?
a = (v – u)/t
a = (67.8 – 0)/5.2
a = 13.04m/s²
Therefore, the acceleration of the spacecraft is 13.04m/s².
5. Determination of the acceleration of the electron.
Data obtained from the question include the following:
Initial velocity (u) = 0
Final velocity (v) = 2.6x10^5m/s
Time (t) = 6.5x10^-7secs
Acceleration (a) =..?
a = (v – u)/t
a = (2.6x10^5 – 0)/ 6.5x10^-7
a = 4x10^11m/s²
Therefore, the acceleration of the electron is 4x10^11m/s².
6. Determination of the acceleration of the truck.
Data obtained from the question include the following:
Initial velocity (u) = 20m/s
Final velocity (v) = 5m/s
Time (t) = 5secs
Acceleration (a) =..?
a = (v – u)/t
a = (5 – 20)/5
a = –15/5
a = –3m/s².
Therefore, the acceleration of the truck is –3m/s².