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A research company desires to know the mean consumption of meat per week among people over age 29. A sample of 2092 people over age 29 was drawn and the mean meet consumption was 2.9 pounds. Assume that the standard deviation is known to be 1.4 pounds. Construct a 95% confidence interval for the mean consumption of meat among people over age 29. Round your answer to one decimal place.

User Laurent VB
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2 Answers

3 votes

Answer:


2.9-1.96(1.4)/(√(2092))=2.84


2.9+1.96(1.4)/(√(2092))=2.96

The confidence interval is given by
2.84 \leq \mu \leq 2.96

Explanation:

Information given


\bar X=2.9 represent the sample mean


\mu population mean


\sigma =1.4 represent the population standard deviation

n=2092 represent the sample size

Confidence interval

The confidence interval is given by:


\bar X \pm z_(\alpha/2)(\sigma)/(√(n)) (1)

Since the Confidence interval is 0.95 or 95%, the significance is
\alpha=0.05 and
\alpha/2 =0.025, and the critical value would be
z_(\alpha/2)=1.96

Replacing the info we got:


2.9-1.96(1.4)/(√(2092))=2.84


2.9+1.96(1.4)/(√(2092))=2.96

The confidence interval is given by
2.84 \leq \mu \leq 2.96

User Yabada
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1 vote

Answer:

The 95% confidence interval for the mean consumption of meat among people over age 29 is between 2.8 pounds and 3 pounds.

Explanation:

We have that to find our
\alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:


\alpha = (1-0.95)/(2) = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of
1-\alpha.

So it is z with a pvalue of
1-0.025 = 0.975, so
z = 1.96

Now, find the margin of error M as such


M = z*(\sigma)/(√(n))

In which
\sigma is the standard deviation of the population and n is the size of the sample.


M = 1.96*(1.4)/(√(2092)) = 0.1

The lower end of the interval is the sample mean subtracted by M. So it is 2.9 - 0.1 = 2.8 pounds

The upper end of the interval is the sample mean added to M. So it is 2.9 + 0.1 = 3 pounds.

The 95% confidence interval for the mean consumption of meat among people over age 29 is between 2.8 pounds and 3 pounds.

User Mr Fett
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