Question

These are the questions

Answer 1

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣠⣤⣤⣤⣤⣤⣶⣦⣤⣄⡀⠀⠀⠀⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⠀⢀⣴⣿⡿⠛⠉⠙⠛⠛⠛⠛⠻⢿⣿⣷⣤⡀⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⠀⣼⣿⠋⠀⠀⠀⠀⠀⠀⠀⢀⣀⣀⠈⢻⣿⣿⡄⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⣸⣿⡏⠀⠀⠀⣠⣶⣾⣿⣿⣿⠿⠿⠿⢿⣿⣿⣿⣄⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⣿⣿⠁⠀⠀⢰⣿⣿⣯⠁⠀⠀⠀⠀⠀⠀⠀⠈⠙⢿⣷⡄⠀

⠀⠀⣀⣤⣴⣶⣶⣿⡟⠀⠀⠀⢸⣿⣿⣿⣆⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣿⣷⠀

⠀⢰⣿⡟⠋⠉⣹⣿⡇⠀⠀⠀⠘⣿⣿⣿⣿⣷⣦⣤⣤⣤⣶⣶⣶⣶⣿⣿⣿⠀

⠀⢸⣿⡇⠀⠀⣿⣿⡇⠀⠀⠀⠀⠹⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⡿⠃⠀

⠀⣸⣿⡇⠀⠀⣿⣿⡇⠀⠀⠀⠀⠀⠉⠻⠿⣿⣿⣿⣿⡿⠿⠿⠛⢻⣿⡇⠀⠀

⠀⣿⣿⠁⠀⠀⣿⣿⡇⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢸⣿⣧⠀⠀

⠀⣿⣿⠀⠀⠀⣿⣿⡇⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢸⣿⣿⠀⠀

⠀⣿⣿⠀⠀⠀⣿⣿⡇⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢸⣿⣿⠀⠀

⠀⢿⣿⡆⠀⠀⣿⣿⡇⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢸⣿⡇⠀⠀

⠀⠸⣿⣧⡀⠀⣿⣿⡇⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣿⣿⠃⠀⠀

⠀⠀⠛⢿⣿⣿⣿⣿⣇⠀⠀⠀⠀⠀⣰⣿⣿⣷⣶⣶⣶⣶⠶⠀⢠⣿⣿⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⣿⣿⠀⠀⠀⠀⠀⣿⣿⡇⠀⣽⣿⡏⠁⠀⠀⢸⣿⡇⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⣿⣿⠀⠀⠀⠀⠀⣿⣿⡇⠀⢹⣿⡆⠀⠀⠀⣸⣿⠇⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⢿⣿⣦⣄⣀⣠⣴⣿⣿⠁⠀⠈⠻⣿⣿⣿⣿⡿⠏⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⠈⠛⠻⠿⠿⠿⠿⠋⠁⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

⡿⣛⣵⣶⡿⠿⠛⠛⠻⠿⢿⣿⣯⣴⣿⣿⣿⣿⣿⣷⣌⢿⣿⣿⣿⣿⣿⣿⣿⣿

⣾⣿⣿⣭⣶⣿⣿⣿⣿⢻⣶⣌⢫⣿⢻⣿⡿⡶⠖⠒⠨⢸⢟⣿⣿⣿⣿⣿⣿⣿

⣿⢿⣿⣿⣿⣿⣿⣿⡿⠿⠿⠿⠆⢃⣾⣯⠮⠂⡒⢠⣠⢄⣙⠝⡻⣿⣿⣿⣿⣿

⣇⣿⣿⣿⣿⣿⡭⠖⢒⠭⠁⠠⠕⢸⢈⣥⣬⠁⠄⢂⢠⣾⣶⠆⣦⣝⡻⣿⣿⣿

⣿⣿⣿⣿⣿⣿⠔⠠⠔⠒⠄⡨⣰⠆⢳⠾⢿⣭⣭⣶⠿⠟⠉⠄⠠⠻⣿⣮⢻⣿

⣿⣷⠶⢒⡞⡱⡚⣠⣎⡁⠴⣊⣠⡆⣷⣿⡷⠖⣀⣠⣶⠶⠞⣁⡀⠄⠘⣿⣷⠹

⣿⣿⣯⣴⡈⢞⢆⣿⣷⣶⣿⡿⠟⣐⣭⣴⠶⢛⣫⣥⣶⣞⢿⣷⣻⠄⠄⢸⣿⡇

⣿⣿⢿⣿⣿⣶⢤⣍⡉⢡⢀⣰⠾⠟⡁⢴⣶⣹⣿⣷⡹⣿⣷⠻⠏⠄⡀⢸⣿⡇

⣿⡟⣸⣿⡿⠋⡺⠠⡃⢀⣋⢥⣶⡻⣿⣯⢿⢷⣙⣿⣽⣰⣿⡏⣷⢰⡇⣼⣿⡇

⣿⣇⣿⣿⡇⣿⡇⠄⠄⠻⣿⣧⢿⣷⡻⣿⣧⢿⣿⡾⣿⣧⣿⣧⡟⣼⣱⣿⣿⡇

⣿⣿⣿⣿⣇⠙⣿⣧⠸⣄⠘⠻⣵⢻⣷⡽⣿⣏⣿⣷⠿⣛⣈⡍⣰⣿⣿⣿⡇

⣿⣿⣿⣿⣿⣆⠈⠛⢷⣼⣿⣷⣌⡻⠛⣓⣛⣉⣤⠴⠿⢛⣡⣸⣿⣿⣿⣿⡿⠡

⠿⣿⣿⣿⣿⣿⣷⡦⣌⣉⣉⣉⣛⣛⣶⣶⣶⢶⣶⣶⣿⣿⠿⣿⣿⡿⠿⢋⣴⡇

⣶⣦⣍⣛⠻⠿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⡿⠾⠿⠿⠿⠿⢓⣛⣩⡅⢰⣿⣿⡇

⣿⣿⣿⣿⣿⣶⣶⣦⣤⣤⣤⣤⣤⣤⣀⣒⠲⢾⣶⣶⣿⣿⠿⠟⣋⣴⣿⣿⣿

88w88 *what have I caught here?

Answer 2

3) 1

4) 0.2

5) 2

6) 1

7) 0.2

Step-by-step explanation:

3)

The molarity of a substance is defined as the number of moles of the substance divided by how many liters the solution is. NaOH has a molar mass of about 40 grams, meaning that 10 grams of it would be 0.25 moles. 0.25/0.25= a molarity of 1.

4)

CO2 has a molar mass of just about 44 grams, meaning that 44 grams of it would be about a mole. 5000mL of solution is 5 liters, meaning that the molarity of this solution would be 1/5=0.2.

5)

HF has a molar mass of about 20, meaning that 20 grams of it is about a mole. 1/0.5=2M.

6)

Calcium flouride has a molar mass of about 78 grams, meaning that 156 grams is about two moles. 2000mL is 2 liters, meaning that this has a molarity of 2/2=1.

7)

Glucose has a molar mass of about 180 grams, meaning that 360 grams of it would be about 2 moles. 2/10=0.2.

Hope this helps!