Answer: The initial temperature of the iron was

Step-by-step explanation:

As we know that,

.................(1)
where,
q = heat absorbed or released
= mass of iron = 360 g
= mass of water = 750 g
= final temperature =

= temperature of iron = ?
= temperature of water =

= specific heat of iron =

= specific heat of water=

Now put all the given values in equation (1), we get
![-360* 0.450* (46.7-x)=[750* 4.184* (46.7-22.5)]](https://img.qammunity.org/2021/formulas/chemistry/high-school/iqdxj91kftcs47fv344963xwldis4ai12t.png)

Therefore, the initial temperature of the iron was
