Question

Which shows one way to determine the factors of 4x3 + x2 – 8x – 2 by grouping? x2(4x + 1) – 2(4x + 1) x2(4x – 1) + 2(4x – 1) 4x2(x + 2) – 1(x + 2) 4x2(x – 2) – 1(x – 2)

Answer 1

see explanation

Explanation:

Given

4x³ + x² - 8x - 2 ( factor the first/second and third/fourth terms )

= x²(4x + 1) - 2(4x + 1) ← first option on list

Finishing the factoring by factoring out (4x + 1) from each term

= (4x + 1)(x² - 2)

Answer 2

x2(4x + 1) – 2(4x + 1)

Explanation:

it's A on edg