Question

A 4 kW vacuum cleaner is powered by an electric motor whose efficiency is 90%. (Note that the electric motor delivers 4 W of net mechanical power to the fan of the cleaner). What is rate at which this vacuum cleaner supplies energy to the room when running

Answer 1

Answer:
`3.6\ kW`

Step-by-step explanation:

Given

Power Supplied
[/tex]

Efficiency of the motor
`\\eta =90\%`

and

`\Rightarrow 0.9=(P_(out))/(4)`

`\Rightarrow P=0.9* 4`

`\Rightarrow P=3.6\ kW`

So, vacuum cleaner delivers a power of
`3.6\ kW`