Question

High speed stroboscopic photographs show that the head of a 244 g golf club is traveling at 57.6 m/s just before it strikes a 45.2 g golf ball at rest on a tee. After the collision, the club head travels (in the same direction) at 39.9 m/s. Find the speed of the golf ball just after impact.

Answer 1

The speed will be "1.06 m/s".

Step-by-step explanation:

The given values are:

Momentum,

m1 = 244 g

m2 = 45.2 g

On applying momentum conservation ,

Let v2 become the final golf's speed.

From Momentum Conservation

⇒
`Total \ initial \ momentum = Total \ final \ momentum`

⇒
`m1* u1 + m2* u2 = m1* v1 + m2* v2`

On putting the estimated values, we get

⇒
`0.244* 57.6+0=0.244* 39.9+45.2* v2`

⇒
`57.844+0=9.7356+45.2* v2`

⇒
`48.1084=45.2* v2`

⇒
`v2=(48.1084)/(45.2)`

⇒
`v2=1.06 \ m/s`