Answer:
vx' = 8.7 m/s
vy' = - 2.9 m/s
Step-by-step explanation:
The average acceleration during a time period is given by the formula:
a = (v' - v)/(t' - t)
where,
a = average acceleration
v' = Final Velocity
v = Initial Velocity
t' = Ending Time
t = Starting Time
Now, for x-component of velocity:
a = ax = 2 m/s²
v' = vx' = ?
v = vx = 0.5 m/s
t' = 4.1 s
t = 0 s
Therefore,
2 m/s² = (vx' - 0.5 m/s)/(4.1s - 0s)
(2 m/s²)(4.1 s) = vx' - 0.5 m/s
8.2 m/s + 0.5 m/s = vx'
vx' = 8.7 m/s
For y- component of velocity:
a = ay = -1 m/s²
v' = vy' = ?
v = vy = 1.2 m/s
t' = 4.1 s
t = 0 s
Therefore,
- 1 m/s² = (vy' - 1.2 m/s)/(4.1s - 0s)
(- 1 m/s²)(4.1 s) = vy' - 1.2 m/s
- 4.1 m/s + 1.2 m/s = vy'
vy' = - 2.9 m/s