Answer:
Percentage of people with IQ greater than 120 is 84.134%
Explanation:
First thing we do here is to calculate the
z-score
Mathematically;
z-score = (x-mean)/SD
here, x = 120, mean = 100 while SD = standard deviation = 20
z-score = (120-100)/20 = 20/20 = 1
The probability we want to calculate is;
P(x > 120) or P(z >1)
we proceed to use the standard score table to get this;
From the standard score table ;
P(z >1) = 0.84134
which is in percentage = 84.134%