Question

An electric field of 2.09 kV/m and a magnetic field of 0.358 T act on a moving electron to produce no net force. If the fields are perpendicular to each other, what is the electron's speed?

Answer 1

The velocity is
`v = 5838 \ m/s`

Step-by-step explanation:

From the question we are told that

The electric field is
`E = 2.09 kV/m = 2.09 *10^(3) \ V/m`

The magnetic field is
`B = 0.358 \ T`

Generally the force experienced by the electron due to the magnetic field is

`F_m = qvB`

Generally the force experienced by the electron due to the electric field is

`F_e = qE`

Since from the question the net force is zero then

`F_e = F_m`

=>
`v = (E)/(B)`

Substituting values

`v = (2.09*10^(3))/(0.358 )`

`v = 5838 \ m/s`