Question

Two dogs play tug of war with a rope toy that has a mass of 0.50 kg. If one dog pulls on the toy with a force of 140.0 N, and the other dog pulls in the opposite direction with a force of 138.0 N, what is the horizontal acceleration of the toy?

Answer 1

Answer:
`4\ m/s^2`

Step-by-step explanation:

Given

mass of toy
`m=0.5\ kg`

Force by first dog
`F_1=140\ N`

Force by second dog is
`F_2=138\ N`

Net force on the dog is

`F_(net)=F_1-F_2=140-138`

`F_(net)=2\ N`

and
`F_(net)=ma`

`a=(F_(net))/(m)`

`a=(2)/(0.5)`

`a=4\ m/s^2`

So, horizontal acceleration of the toy is
`4\ m/s^2`