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What are the exact solutions of x2 − 5x − 7 = 0, where x equals negative b plus or minus the square root of b squared minus 4 times a times c all over 2 times a?

x = the quantity of negative 5 plus or minus the square root of 3 all over 2
x = the quantity of 5 plus or minus the square root of 3 all over 2
x = the quantity of negative 5 plus or minus the square root of 53 all over 2
x = the quantity of 5 plus or minus the square root of 53 all over 2

User Jtoberon
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2 Answers

2 votes

Answer:

x = the quantity of 5 plus or minus the square root of 53 all over 2

Explanation:

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User Kulnor
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Using The Almighty Formula (attached)

Note the symbol ^ is used to denote a raise to power

Where from the equation given x^2-5x-7

With a,b,c coefficients

a=1 b=-5 c=-7

From the Almighty Formula

√b^2-4ac=√(-5)^2-4(-7)=√53

Substituting in the Almighty Formula

-(-5) ±√53/2(1)= 5±√53/2

x=5+√53/2 and x=5-√53/2

What are the exact solutions of x2 − 5x − 7 = 0, where x equals negative b plus or-example-1
User Caerbannog
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