Answer:
tanθ=2√2
Explanation:
cosθ= 1/3, and θ is acute;
cos²θ=1/9
sin²θ+cos²θ=1
sin²θ=1-cos²θ=1-1/9=8/9
=> sinθ=√(8/9)=2√2 /3
tanθ=sinθ/cosθ
tanθ=(2√2 /3)/(1/3)=2√2
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