Question

Two vectors A and B are such that A =1,B=2,A.B=1 find angle

Answer 1

Answer:
`60^(\circ)`

Step-by-step explanation:

Given

`\mid\Vec{A}\mid=1`

`\mid\Vec{B}\mid=2`

And
`A\cdot B=1`

We know
`\vec{A}\cdot \vec{B}=\mid\Vec{A}\mid\mid\Vec{B}\mid\cos \theta`

Where
`\theta` is the angle between them

Substituting the values

`1=1* 2\cos \theta`

`\cos \theta =(1)/(2)`

`\theta =60^(\circ)`

Thus the angle between
`A` and
`B` is
`60^(\circ)`