Answer:
70°
Explanation:
∠A =112°,
Exterior angle to angle B is 2x, therefore ∠B = 180 -2x (angle on straight line)
Exterior angle to angle C is 2x + 12, therefore ∠C = 180 -(2x +12) (angle on straight line) = 180 - 12 -2x = 168 - 2x
∠A + ∠B + ∠C = 180 (sum o angles in a triangle)
112 + 180 - 2x + 168 - 2x = 180
460 - 4x = 180
4x = 460 - 180 = 280
x = 280/4 = 70
x = 70°