Question

Solve 5x^2-4x-2=0 by completing the square

Answer 1

Hello

Here's the answer:

2x^2 + 5x + 2 = 0\\
2x^2+4x+x+2=0\\
2x(x+2)+1(x+2)=0\\
(2x+1)(x+2)=0\\
x=-\frac{1}{2} \vee x=-2

x^2-4x+1=0\\
x^2-4x+4-3=0\\
(x-2)^2=3\\
x-2 =\sqrt3 \vee x-2=-\sqrt3\\
x=2+\sqrt3 \vee x=2-\sqrt3

Explanation: