Question

- Find the length of the side a of the triangle ABC given that <A= 70°,

<B = 50° and b = 4cm.​

Answer 1

4.91 cm

Explanation:

The Law of Sines tells you ...

a/sin(A) = b/sin(B)

a = b(sin(A)/sin(B)) = (4 cm)(sin(70°)/sin(50°))

a ≈ 4.91 cm