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3 votes
Hiii guys i need help with my homewrok
-9\leq 7-8x

User Rgngl
by
8.0k points

1 Answer

1 vote

Answer:

The answer is x ≤ 2.

Explanation:

Firstly, you have to move the unrelated term to the other side :


- 9 \leqslant 7 - 8x


- 9 - 7 \leqslant - 8x


- 16 \leqslant - 8x

Next you can solve it :


- 8x \geqslant - 16


x \leqslant - 16 / - 8


x \leqslant 2

*Remember to change the symbol, when it is dividing by a negative value

User Popstr
by
8.3k points

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