Question

Hiii guys i need help with my homewrok
`-9\leq 7-8x`

Answer 1

The answer is x ≤ 2.

Explanation:

Firstly, you have to move the unrelated term to the other side :

`- 9 \leqslant 7 - 8x`

`- 9 - 7 \leqslant - 8x`

`- 16 \leqslant - 8x`

Next you can solve it :

`- 8x \geqslant - 16`

`x \leqslant - 16 / - 8`

`x \leqslant 2`

*Remember to change the symbol, when it is dividing by a negative value