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How many hydrogen atom are present in 1.53 g of water

User Ambar
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1 Answer

6 votes

Answer:


=1.02x10^(23) atoms\ H

Step-by-step explanation:

Hello,

In this case, for water, whose molar mass is 18 g/mol, we can find two moles of hydrogen in one mole of water, therefore, for us compute the atoms, we should also use the Avogadro's number as shown below:


=1.53gH_2O*(1molH_2O)/(18gH_2O)*(2molH)/(1molH_2O) *(6.022x10^(23)atoms\ H)/(1molH) \\\\=1.02x10^(23) atoms\ H

Regards.

User ApceH Hypocrite
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