Question

PLEASE ANWSER I WILL GOVE YOU POINTS ! And a like Many statues are made out of calcium (marble).Acid rain contains sulfuric acid,which reacts with the calcium carbonate.how many grams of calcium carbonate are consumed if 500.g of sulfuric acid fall onto the statue ? 2CaCO3+1H2SO4->1co2+1H2O+CaSo4

Answer 1

1.02 × 10³ g

Step-by-step explanation:

Step 1: Write the balanced equation

2 CaCO₃ + H₂SO₄ ⇒ CO₂ + H₂O + CaSO₄

Step 2: Calculate the moles corresponding to 500 g of sulfuric acid

The molar mass of sulfuric acid is 98.08 g/mol.

`500g * (1mol)/(98.08g) = 5.10mol`

Step 3: Calculate the moles of calcium carbonate that react with 5.10 moles of sulfuric acid

The molar ratio of CaCO₃ to H₂SO₄ is 2:1. The moles that react of calcium carbonate are (2/1) × 5.10 mol = 10.2 mol

Step 4: Calculate the mass corresponding to 10.2 moles of calcium carbonate

The molar mass of calcium carbonate is 100.09 g/mol.

`10.2mol * (100.09 g)/(mol) =1.02 * 10^(3) g`