64.8k views
0 votes
Watching tv: in 2012, the general social survey asked a sample of 1310 people how much time they spend\t watching tv each day. The mean number of hours was 2.8 with a standard deviation of 2.6. A sociologist claims that people watch a mean of 3 hours of TV per day. Do the data provide sufficient evidence to conclude that the mean hours of TV watched per day is less the claim? Use the a=0.5 level of significance and the P-value method with the TI-84 Plus calculator.

(a) State the appropriate null and alternate hypotheses.

H0: Mu = 3
H1: Mu < 3

This hypothesis test is a _____ test.

(b) Compute the P-value. Round the answer to at least four decimal places

P-value =

User DJ Forth
by
7.1k points

1 Answer

5 votes

Answer:

a) Null hypothesis:
\mu \geq 3

Alternative hypothesis:
\mu < 3

This hypothesis test is a left tailed test.

b)
t=(2.8-3)/((2.6)/(√(1310)))=-2.784

The p value for this case can be calculated with this probability:


p_v =P(z<-2.784)=0.0027

We can conduct the test with the Ti84 using the following steps:

STAT>TESTS>T-test>Stats

We input the value
\mu_o =3, \bar X= 2.8, s_x = 2.6, n=1310 and for the alternative we select
< \mu_o. Then press Calculate.

And we got the same results.

Explanation:

Information given


\bar X=2.8 represent the sample mean


s=2.6 represent the population standard deviation


n=1310 sample size


\mu_o =3 represent the value to test


\alpha=0.5 represent the significance level for the hypothesis test.

t would represent the statistic


p_v represent the p value for the test

Part a) System of hypothesis

We want to test if the true mean is less than 3, the system of hypothesis would be:

Null hypothesis:
\mu \geq 3

Alternative hypothesis:
\mu < 3

This hypothesis test is a left tailed test.

Part b

The statistic is given by:


t=(\bar X-\mu_o)/((s)/(√(n))) (1)

Replacing the info given we got:


t=(2.8-3)/((2.6)/(√(1310)))=-2.784

The p value for this case can be calculated with this probability:


p_v =P(z<-2.784)=0.0027

We can conduct the test with the Ti84 using the following steps:

STAT>TESTS>T-test>Stats

We input the value
\mu_o =3, \bar X= 2.8, s_x = 2.6, n=1310 and for the alternative we select
< \mu_o. Then press Calculate.

And we got the same results.

User Tushar Patel
by
6.3k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.