Question

A cylindrical metal pipe has a diameter of 8.4 millimeters

and a height of 10 millimeters. Ahole cut out of the center

has a diameter of 6 millimeters,

What is the volume of metal in the pipe? Use 3.14 for

and round the answer to the nearest tenth of a cubic

millimeter

8.4 mm

© 282.6 mm

271.3 mm

553.9 mm

836.5 mm

thand

Next

Submit

Answer 1

B. 271.3
`mm^(3)`

Explanation:

Volume of the outer cylinder minus the volume of the inner cylinder returns the volume of the metal outer ring that surrounds the hole.

Answer 2

C. 271.44
`mm^3`

Explanation:

We need to first find the volume of the pipe, then find the volume of the hole and then subtract the volume of the hole from the volume of the pipe.

The diameter of the pipe is 8.4 mm. This means its radius is:

8.4/2 = 4.2 mm

The height of the pipe is 10 mm

The volume of a cylinder is given as:

`V = \pi r^2h`

where r = radius

h - height

Therefore, the volume of the cylinder without the hole is:

`V = \pi * 4.2^2 * 10\\\\V = 554.18 mm^3`

The diameter of the hole is 6 mm. Its radius is:

6/2 = 3 mm

The volume of the hole is:

`V = \pi * 3^2 * 10\\\\V = 282.74 mm^3`

The volume is:

554.18 - 282.74 = 271.44
`mm^3`