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Find the 7th term of the geometric sequence with a3= -45 and a5= -405

User MihaiV
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1 Answer

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Answer:

Explanation:

let a be the first term and r be common ratio.


a_(3)=ar^2=-45\\a_(5)=ar^4=-405\\divide\\(ar^4)/(ar^2) =(-405)/(-45) =9\\r^2=9\\r=\pm3\\9a=-45\\a=-5\\a_(7)=ar^(7-1)=ar^6=ar^4 * r^2=-405 * 9=-3645

User Chuck Batson
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