Answer:
Explanation:
The relevant relation is that the product of distances from the point of intersection of secants to the two points of intersection of each with the circle is a constant. The point of tangency counts as both points of intersection.
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By way of example, the product of distances to the circle for the tangent segment is 10·10 = 100
This is also the product of the distances on the secant that intersects the tangent:
100 = 5(5+x+9)
20 = x +14 . . . . . divide by 5
x = 6 . . . . . . . . . . subtract 14
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The same is true when the secants intersect inside the circle:
6·9 = y·3
y = 18 . . . . . . divide by 3