Answer:
Total paper required = 165 cm²
Explanation:
Paper required to cover the entire block = (Surface area of the prism at the base - area of the top of the prism) + Lateral surface area of the pyramid
Surface area of the rectangular prism = 2(lb + bh + hl)
(here l, b, h are the length, width and height respectively)
= 2(5×5 + 5×4 + 4×5)
= 2(25 + 20 + 20)
= 2×65
= 130 cm²
Area of the top of the prism = (side)²
= 5²
= 25 cm²
Lateral area of the square pyramid = 4 × Area of one lateral side
= 4 ×
![[(1)/(2)(\text{Base})(\text{Height})]](https://img.qammunity.org/2021/formulas/mathematics/high-school/nv0q19sku1dr17hi3w44xsm6gqrr67b335.png)
= 4 ×
![[(1)/(2)(5)(6)]](https://img.qammunity.org/2021/formulas/mathematics/high-school/982j7uhvrtgqj8s2x0g09xeawmsiyrxlf0.png)
= 60 cm²
Total paper required = (130 - 25) + 60
= 105 + 60
= 165 cm²