Question

Find the area A of △JKL with vertices J(−4,10), K(0,3), and L(−4,−2).

Answer 1

24 Square Units

Explanation:

Answer 2

24 sq. u.

Explanation:

1)For this triangle area, let's use the classic Euclidean formula:

`\Delta \: area=(b*h)/(2)`

2) Let's measure the lenght of the base, taking the y coordinate of J vertex and L Vertex

`|10-(-2)|=|12|=12`

3) Similarly to the height, taking the K and its distance to the base

|0-(-4)|=|4|=4

4) Plugging them in:

`\Delta \: area=(12*4)/(2)=24`