Question

A block of ice is sliding down a ramp of slope 45° to the horizontal. At the bottom of the ramp, the block strikes a wall with a force of 3.4 N. What is the mass of the ice? Assume the force of friction is not significant.

Answer 1

Mass, m = 0.49 kg

Step-by-step explanation:

It is given that,

A block of ice is sliding down a ramp of slope 45° to the horizontal. At the bottom of the ramp, the block strikes a wall with a force of 3.4 N.

We need to find the mass of the ice.

On a sloping surface, the force with which it strikes is given by :

`F=mg\cos\theta\\\\m=(F)/(g\cos\theta)\\\\m=(3.4)/(9.8* \cos(45))\\\\m=0.49\ kg`

So, the mass of the ice block is 0.49 kg.